Matematika B - 2016. ljeto, 8.

$n=\frac{1}{2}p-3n=\backslash frac\{1\}\{2\}\; p-3$

$n=2p-3n=2\; p-3$

$n=\frac{1}{2}p-1n=\backslash frac\{1\}\{2\}\; p-1$

$n=2p-1n=2\; p-1$