Matematika B - 2010. ljeto, 12.

$a=\frac{s-b-c}{2}a=\backslash frac\{s-b-c\}\{2\}$

$a=2(s-b-c)a=2(s-b-c)$

$a=2s-b-ca=2\; s-b-c$

$a=2s+\frac{b+c}{2}a=2\; s+\backslash frac\{b+c\}\{2\}$