Matematika B - 2018. jesen, 7.

$a=\frac{b+3c}{2}a=\backslash frac\{b+3\; c\}\{2\}$

$a=\frac{3b-c}{2}a=\backslash frac\{3\; b-c\}\{2\}$

$a=\frac{3(b+c)}{2}a=\backslash frac\{3(b+c)\}\{2\}$

$a=\frac{b+c-3}{2}a=\backslash frac\{b+c-3\}\{2\}$