Matematika A - 2018. ljeto, 14.

$f(x)=-{\log }_{2}xf(x)=-\backslash log\; \_\{2\}\; x$

$f(x)=-{\log }_{0.5}xf(x)=-\backslash log\; \_\{0.5\}\; x$

$f(x)={\log }_{1.5}xf(x)=\backslash log\; \_\{1.5\}\; x$

$f(x)={\log }_{4}xf(x)=\backslash log\; \_\{4\}\; x$