Matematika A - 2011. ljeto, 14.

$(x+2)(x+5)=0(x+2)(x+5)=0$

$\mathrm{\mid }2x-3\mathrm{\mid }=2|2\; x-3|=2$

${\left(\frac{1}{2}\right)}^{2x+3}=\frac{1}{4}\backslash left(\backslash frac\{1\}\{2\}\backslash right)^\{2\; x+3\}=\backslash frac\{1\}\{4\}$

$\log (x-3)=1\backslash log\; (x-3)=1$