Matematika A - 2017. jesen, 2.

za $x={\log }_{3}0.41x=\backslash log\; \_\{3\}\; 0.41$

za $x=1-\sqrt{2}x=1-\backslash sqrt\{2\}$

za $x=\sqrt[3]{0.25}x=\backslash sqrt[3]\{0.25\}$

za $x=2^{-0.5}x=2^\{-0.5\}$