Matematika A - 2011. jesen, 5.

$b=\frac{c-ak}{k}b=\backslash frac\{c-a\; k\}\{k\}$

$b=\frac{ak-c}{k}b=\backslash frac\{a\; k-c\}\{k\}$

$b=\frac{k}{c-ak}b=\backslash frac\{k\}\{c-a\; k\}$

$b=\frac{k}{ak-c}b=\backslash frac\{k\}\{a\; k-c\}$