Kemija - 2015./16. jesen - 43.

$\rho =pM-RT\backslash rho=p\; M-R\; T$

$\rho =RT-pM\backslash rho=R\; T-p\; M$

$\rho =\frac{RT}{pM}\backslash rho=\backslash frac\{R\; T\}\{p\; M\}$

$\rho =\frac{pM}{RT}\backslash rho=\backslash frac\{p\; M\}\{R\; T\}$