Kemija - 2010./11. jesen - 2.

$4{\mathrm{C}\mathrm{l}}_{2}4\; \backslash mathrm\{~Cl\}\_\{2\}$

$1{\mathrm{C}\mathrm{l}}_{4}1\; \backslash mathrm\{~Cl\}\_\{4\}$

$4\mathrm{C}\mathrm{l}4\backslash mathrm\{~Cl\}$

$2{\mathrm{C}\mathrm{l}}_{2}2\; \backslash mathrm\{~Cl\}\_\{2\}$