Jednadžba stanja plina - 2.

$N_{\mathrm{A}}=6,022\cdot {10}^{23}{\mathrm{m}\mathrm{o}\mathrm{l}}^{-1}N\_\{\backslash mathrm\{A\}\}=6,022\; \backslash cdot\; 10^\{23\}\; \backslash mathrm\{~mol\}^\{-1\}$

$R=8,314\mathrm{J}\mathrm{/}\mathrm{K}\mathrm{m}\mathrm{o}\mathrm{l}R=8,314\; \backslash mathrm\{~J\}\; /\; \backslash mathrm\{K\}\; \backslash mathrm\{mol\}$

$u=1,6605\cdot {10}^{-27}\mathrm{k}\mathrm{g}u=1,6605\; \backslash cdot\; 10^\{-27\}\; \backslash mathrm\{~kg\}$

$k_{\mathrm{B}}=1,38\cdot {10}^{-23}\mathrm{J}\mathrm{/}\mathrm{K}k\_\{\backslash mathrm\{B\}\}=1,38\; \backslash cdot\; 10^\{-23\}\; \backslash mathrm\{~J\}\; /\; \backslash mathrm\{K\}$